用Ajax读取XML格式的数据

2022-07-15 80酷酷网 80kuku.com

　　ajax|xml|数据CODE:<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<title>Ajax Hello World</title>
<script type="text/javascript">
var xmlHttp;
function createXMLHttpRequest(){
    if(window.ActiveXObject){
        xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
    }
    else if(window.XMLHttpRequest){
        xmlHttp = new XMLHttpRequest();
    }
}
function startRequest(){
    createXMLHttpRequest();
    try{
        xmlHttp.onreadystatechange = handleStateChange;
        xmlHttp.open("GET", "data.xml", true);
        xmlHttp.send(null);
    }catch(exception){
        alert("您要访问的资源不存在!");
    }
}
function handleStateChange(){
    if(xmlHttp.readyState == 4){
        if (xmlHttp.status == 200 || xmlHttp.status == 0){
            // 取得XML的DOM对象
            var xmlDOM = xmlHttp.responseXML;
            // 取得XML文档的根
            var root = xmlDOM.documentElement;
            try
            {
                // 取得<info>结果
                var info = root.getElementsByTagName('info');
                // 显示返回结果
                alert("responseXML's value: " + info[0].firstChild.data);
            }catch(exception)
            {
            }
        }
    }
}
</script>
</head>
<body>
    <div>
        <input type="button" value="return ajax responseXML's value"
                />
    </div>
</body>
</html>
server.xml
[复制此代码]CODE:
<?xml version="1.0" encoding="GB2312" ?>
<root>
    <info>hello world!</info>
</root>