存储过程|破解if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[p_GetPassword]') and OBJECTPROPERTY(id, N'IsProcedure') = 1)
drop procedure [dbo].[p_GetPassword]
GO

/*--穷举法破解 SQL Server 用户密码

可以破解中文,特殊字符,字符+尾随空格的密码
为了方便显示特殊字符的密码,在显示结果中,显示了组成密码的ASCII

理论上可以破解任意位数的密码
条件是你的电脑配置足够,时间足够

--邹建 2004.08(引用请保留此信息)--*/

/*--调用示例

--测试特殊字符
declare pwd sysname
set pwd=char(0)+'a '
exec sp_password null,pwd,'sa'
exec p_GetPassword

--测试带空格的密码
exec sp_password null,'a  ','sa'
exec p_GetPassword

--测试中文
exec sp_password null,'我 ','sa'
exec p_GetPassword

--清除密码
exec sp_password null,null,'sa'
--*/
create proc p_GetPassword
username sysname=null,--用户名,如果不指定,则列出所有用户
pwdlen int=3--密码破解的位数,默认只破解3位及以下的密码
as
--生成要破解的密码的用户表
select name,password
,type=case when xstatus&2048=2048 then 1 else 0 end
,jm=case when password is null or datalength(password)<46
then 1 else 0 end
,pwdstr=case when datalength(password)<46
then cast(password as sysname)
else cast('' as sysname) end
,pwd=cast('' as varchar(8000))
into #pwd
from master.dbo.sysxlogins a
where srvid is null
and name=isnull(username,name)

--生成临时表
select top 255 id=identity(int,0,1) into #t from sysobjects a,sysobjects b
alter table #t add constraint PK_#t primary key(id)

--清理不需要的字符
if not exists(select 1 from #pwd where type=1)
delete from #t where id between 65 and 90 or id between 129 and 254

--密码破解处理
declare l int
declare s1 varchar(8000),s2 varchar(8000),s3 varchar(8000),s4 varchar(8000)

--破解1位密码
select l=0
,s1='id=a.id'
,s2='#t a'
,s3='char(b.id)'
,s4='cast(b.id as varchar)'
exec('
update pwd set jm=1,pwdstr='+s3+'
,pwd='+s4+'
from #pwd pwd,#t b
where pwd.jm=0
and pwdcompare('+s3+',pwd.password,pwd.type)=1
')

--破解超过2位的密码
while exists(select 1 from #pwd where jm=0 and l<pwdlen-1)
begin
select l=l+1
,s1=s1+',id'+cast(l as varchar)
+'='+char(l/26+97)+char(l%26+97)+'.id'
,s2=s2+',#t '+char(l/26+97)+char(l%26+97)
,s3=s3+'+char(b.id'+cast(l as varchar)+')'
,s4=s4+'+'',''+cast(b.id'+cast(l as varchar)+' as varchar)'
exec('
select '+s1+' into #tt from '+s2+'
update pwd set jm=1,pwdstr='+s3+'
,pwd='+s4+'
from #pwd pwd,#tt b
where pwd.jm=0
and pwdcompare('+s3+',pwd.password,pwd.type)=1
')
end

--显示破解的密码
select 用户名=name,密码=pwdstr,密码ASCII=pwd
from #pwd
go